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SIOUX CITY vs. SANIBEL
Cost of Living Comparison

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Cost of Living Calculator - Sioux City, Iowa vs Sanibel, Florida

The cost of living in Sanibel, Florida is 117.9% more expensive than Sioux City, Iowa.

You would need a salary of $174,390 in Sanibel, Florida to maintain the standard of living you have in Sioux City, Iowa.

Comparison highlights

• Overall, Sanibel, Florida is more expensive than Sioux City, Iowa
• Median Home Cost is the biggest factor in the cost of living difference.

Median Home Cost
546% more expensive in Sanibel
than in Sioux City, Iowa

Sioux City, IA vs Sanibel, FL

Compared to Sioux City, Sanibel is:

Homeowner

No Child Care, Taxes not Considered

117.9% higher

Child Care, Taxes not Considered

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Child Care, Taxes Considered

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No Child Care, Taxes Considered

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Renter

No Child Care, Taxes not Considered

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Child Care, Taxes not Considered

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Child Care, Taxes Considered

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No Child Care, Taxes Considered

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Food

24.4% higher

Housing (Homeowner)

562.2% higher

Housing (Rent)

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Median Home Cost

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Utilities

5.9% higher

Commute

38.1% higher

Health

18.4% higher

Taxes

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Childcare

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Personal

0.3% higher

Cost of Food

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