Keosauqua, IA Cost of Living


0 Reviews



Download our custom City Report to see exclusive
data on cost of living, crime, climate, and more.
United States / Iowa / No Metro Area / Van Buren County / Keosauqua / Zip Codes

Keosauqua cost of living score
75
Less expensive
25.0% lower
than the US average
6.4% lower
than the Iowa average
Keosauqua, Iowa gets a BestPlaces Cost of Living score of 75, which means the total cost of housing, food, childcare, transportation, healthcare, taxes, and other necessities is 25.0% lower than the U.S. average and 6.4% higher than the average for Iowa.

Keosauqua, IA

Housing costs in Keosauqua?
A typical home costs $157,900, which is 53.3% less expensive than the national average of $338,100 and 19.0% less expensive than the average Iowa home, at $194,900. Renting a two-bedroom unit in Keosauqua costs $800 per month, which is 44.1% cheaper than the national average of $1,430 and 16.3% cheaper than the state average of $930.

Can I afford Keosauqua?
To live comfortably in Keosauqua, Iowa, a minimum annual income of $30,240 for a family, and $28,400 for a single person is recommended.

What does A.I. say about Keosauqua?
Keosauqua, IA has a relatively low cost of living compared to other cities in the United States. The median home value is just over $94,000 and the median household income is around $44,000. Additionally, groceries and essential items are quite affordable in the area. Utility costs are also lower than average due to an abundance of renewable energy sources in the area. This makes Keosauqua an especially attractive area for those who want to save money while still enjoying a comfortable lifestyle.
   Cost of living score
     CategoriesKeosauquaIowaUnited States
  75.080.1100.0
  93.294.4100
  117.3108.2100.0
  42.355.4100.0
  $157,900$194,900$338,100
  102.1%98.5%100.0%
  73.371.4100.0
  82.896.3100.0

   100=National Average

   Average Rent by Bedroom Size
Crime
Compare Keosauqua, IA cost of living
Compare food, housing, utilities, and more in Keosauqua, Iowa to any other city in the US.