Seymour, IA Cost of Living


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United States / Iowa / No Metro Area / Wayne County / Seymour / Zip Codes

Seymour cost of living score
72.3
Less expensive
27.7% lower
than the US average
9.7% lower
than the Iowa average
Seymour, Iowa gets a BestPlaces Cost of Living score of 72.3, which means the total cost of housing, food, childcare, transportation, healthcare, taxes, and other necessities is 27.7% lower than the U.S. average and 9.7% higher than the average for Iowa.

Seymour, IA

Housing costs in Seymour?
A typical home costs $108,600, which is 67.9% less expensive than the national average of $338,100 and 44.3% less expensive than the average Iowa home, at $194,900. Renting a two-bedroom unit in Seymour costs $790 per month, which is 44.8% cheaper than the national average of $1,430 and 17.7% cheaper than the state average of $930.

Can I afford Seymour?
To live comfortably in Seymour, Iowa, a minimum annual income of $20,880 for a family, and $24,000 for a single person is recommended.

What does A.I. say about Seymour?
The cost of living in Seymour, IA is slightly above the national average. The median home value is $114,800, which is higher than the US median home value of $184,700. The median monthly rental cost for a one-bedroom apartment in Seymour is $500, slightly more expensive than the US monthly rental cost of $1,000. Groceries and healthcare costs are also slightly above the national average. Despite a higher overall cost of living than other parts of the country, Seymour is still an affordable place to live and offers many advantages including a small town atmosphere and proximity to larger cities in Iowa.
   Cost of living score
     CategoriesSeymourIowaUnited States
  72.380.1100.0
  92.294.4100
  117.1108.2100.0
  16.055.4100.0
  $108,600$194,900$338,100
  100.8%98.5%100.0%
  75.371.4100.0
  81.496.3100.0

   100=National Average

   Average Rent by Bedroom Size
Crime
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