Shrewsbury, VT Rankings


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Shrewsbury is a town located in Rutland County, Vermont, United States. It has a population of 1,612 people and is ranked #3 out of 34 towns in the county by Bestplaces.net. The rankings take into account factors such as cost of living, crime rate, education level, housing market and overall quality of life. Shrewsbury has an excellent quality of life score with plenty of green space and parks to explore. It also offers amenities such as recreational activities for all ages and easy access to major cities and airports. Furthermore, its low crime rate makes it a safe place to live and raise a family. With its great scenery and peaceful atmosphere, Shrewsbury is a top-ranked destination for those looking for a pleasant home environment.

Best Places ranks thousands of places to live based on analysis, data and key statistics from the U.S. Census and our Best Places To Live Expert Insights.


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